# n,k = input().split()
# n = int(n)
# k = int(k)
# for i in range (1,n+1):
# for j in range(1,n+1):
# if (i == 1) or (i == n) or (j == n) or (j == 1):
# print('*', end='')
# elif (i+j-1) % k == 0:
# print('*', end='')
# else:
# print(' ', end='')
# print()
#
# '''
# list : array
# data = [10, 20, 30]
# data[0] => 10
# data[1] => 20
# len(data) = 3
# data[0] = 50
# data = [50, 20, 30]
# data.pop() => 30
#
# * input, output, edit free
# tuple : array
# data = (10, 20, 30)
# data[0] => 10
# data[0] = 50(X)
#
# * input, edit cannot, can only view
#
# dictionary : structure
# dict = {key, value}
# dict{'apple': 155}
# dict['apple'] = 155
# '''
# data = []
# print(data)
# data.append(10)
# print(data)
# data.append(50)
# print(data)
# data.append(20)
# print(data)
# data.append(5)
# print(data)
# data.append(-20)
# print(data)
# data.append(-70)
# print(data)
# data.append(20)
# print(data)
#
# data.sort() # up
# print('sorted', data)
# data.sort(reverse=True)
# print('reverse', data)
#
# data.pop()
# print(data)
#
# data.pop(2)
# print(data)
#
# data.append([10, 20, 20, 20, 30])
# print(data)
# print(data[5][0])
#
# # json file format
# print(data[5].count(20))
# data = (10, 20, 30)
# print(data)
# print(data[0])
#
# dict = {}
# print(dict)
# dict['apple'] = ['team cook', 'rank 1']
# dict['tesla'] = 240
# dict['schd'] = 100
# dict['O'] = 240
# print(dict)
#
# print(dict.keys())
# print(dict.values())
#
# print(dict.get('apple'))
# # x = dict.get('apple')
# # x += 500
# # dict['apple'] = x
# print(dict)
# data = input()
# data = list(data)
# for i in range (26):
# print((chr(97+i)), data.count(chr(97+i)),sep=':')
# dictionary 를 사용한 코드업 1420 풀이 방법 (이름이 같지 않을 때)
# v = {}
# a = []
# n=int(input())
# for i in range(n):
# data = input().split()
# name = data[0]
# score = int(data[1])
# v[name]=score
#
# p = list(v.values())
#
# for i in range(n):
# a.append(p[i])
# a.sort()
# a.sort(reverse=True)
# q = list(v.keys())
# w = list(v.values())
#
# for i in range (n):
# if w[i]==a[2]:
# print(q[i])
# else:
# continue
# dictionary 를 사용 하지 않은 코드업 1420 풀이 방법
v = []
n=int(input())
for i in range(n):
data = input().split()
data[1]=int(data[1])
v.append(data)
for i in range(n):
v.sort(data[1][i])
print(v)
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