# 6-3
# menu = {'Americano': 3000, 'IceAmericano': 3500, 'Cappuccino': 4000, "CafeLatte" : 4500, 'Espresso' : 3600 }
# menu.update(Americano='3,000원', IceAmericano='3,500원', Cappuccino='4,000원', CafeLatte='4,500원', Espresso='3,600원')
# for key in menu:
# print('%-20s'%key, '가격 :', menu.get(key))
#6-3.2
# menu = {'Americano': 3000, 'IceAmericano': 3500, 'Cappuccino': 4000, 'CafeLatte': 4500, 'Espresso': 3600}
# menu.update(Americano='3,000원', IceAmericano='3,500원', Cappuccino='4,000원', CafeLatte='4,500원', Espresso='3,600원')
# x = input('위의 메뉴 중 하나를 선택하세요:')
# if x in menu:
# print(x, '는', menu.get(x), '입니다.')
# print('결제를 부탁합니다.')
#
# else:
# print('미안합니다')
# print(x, '는', '메뉴에 없습니다')
# menu1 = ['Americano', 'Ice Americano', 'Cappuccino', 'Caffe Latte', 'Espresso']
# cost = ['3,000', '3,500', '4,000', '4,500', '3,600']
# menu = dict(zip(menu1, cost))
# print(menu)
# dict = {'A':100, 'B':200, 'C':300, 'D':400}
# print(dict.keys(), type(dict.keys()))
# print(dict.values(), type(dict.values()))
#
# keys = list(dict.keys())
# values = list(dict.values())
# print(keys, values)
# print(type(keys), type(values))
#
# x = input()
# if x in dict:
# print(x,'는 ', dict.get(x), '입니당')
# # print('x', dict.get(x))
#
# else:
# print('Has not')
# 6-10
# b = (1, 2, 5, 4, 3, 2, 1, 4, 7, 8, 9, 9, 3, 7, 3)
# a = (1, 2, 5, 4, 3, 2, 9, 4, 7, 8, 9, 9, 3, 7, 3)
#
# # Solution01
# max = -1
# value = -1
#
# vA = list(set(list(a)))
# vA.sort()
#
# for i in range(len(vA)):
# if a.count(vA[i]) >= max:
# max = a.count(vA[i])
# value = vA[i]
#
# print(max, value)
# maxNumber = -1 # 최대개수
# maxValue = -1 # 최대값
# for i in range(len(a)):
# if a.count(a[i]) >= maxNumber:
# if maxNumber <= a.count(a[i]):
# maxValue = a[i]
# maxNumber = a.count(a[i])
#
# print(maxNumber, maxValue)
# dictNumber = {}
#
# for i in range(len(a)):
# if a[i] in dictNumber:
# dictNumber[a[i]] += 1
# else:
# dictNumber[a[i]] = 1
# values = dictNumber.values()
#
# if dictNumber.get(3) == dictNumber.get(9):
# print('가장 많이 나타나는 원소는:', 9)
# else:
# print("가장 많이 나타나는 원소는", )